Optimal. Leaf size=149 \[ \frac {5 a^2 (8 A b-a B) x \sqrt {a+b x^2}}{128 b}+\frac {5 a (8 A b-a B) x \left (a+b x^2\right )^{3/2}}{192 b}+\frac {(8 A b-a B) x \left (a+b x^2\right )^{5/2}}{48 b}+\frac {B x \left (a+b x^2\right )^{7/2}}{8 b}+\frac {5 a^3 (8 A b-a B) \tanh ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a+b x^2}}\right )}{128 b^{3/2}} \]
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Rubi [A]
time = 0.04, antiderivative size = 149, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 4, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.210, Rules used = {396, 201, 223,
212} \begin {gather*} \frac {5 a^3 (8 A b-a B) \tanh ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a+b x^2}}\right )}{128 b^{3/2}}+\frac {5 a^2 x \sqrt {a+b x^2} (8 A b-a B)}{128 b}+\frac {x \left (a+b x^2\right )^{5/2} (8 A b-a B)}{48 b}+\frac {5 a x \left (a+b x^2\right )^{3/2} (8 A b-a B)}{192 b}+\frac {B x \left (a+b x^2\right )^{7/2}}{8 b} \end {gather*}
Antiderivative was successfully verified.
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Rule 201
Rule 212
Rule 223
Rule 396
Rubi steps
\begin {align*} \int \left (a+b x^2\right )^{5/2} \left (A+B x^2\right ) \, dx &=\frac {B x \left (a+b x^2\right )^{7/2}}{8 b}-\frac {(-8 A b+a B) \int \left (a+b x^2\right )^{5/2} \, dx}{8 b}\\ &=\frac {(8 A b-a B) x \left (a+b x^2\right )^{5/2}}{48 b}+\frac {B x \left (a+b x^2\right )^{7/2}}{8 b}+\frac {(5 a (8 A b-a B)) \int \left (a+b x^2\right )^{3/2} \, dx}{48 b}\\ &=\frac {5 a (8 A b-a B) x \left (a+b x^2\right )^{3/2}}{192 b}+\frac {(8 A b-a B) x \left (a+b x^2\right )^{5/2}}{48 b}+\frac {B x \left (a+b x^2\right )^{7/2}}{8 b}+\frac {\left (5 a^2 (8 A b-a B)\right ) \int \sqrt {a+b x^2} \, dx}{64 b}\\ &=\frac {5 a^2 (8 A b-a B) x \sqrt {a+b x^2}}{128 b}+\frac {5 a (8 A b-a B) x \left (a+b x^2\right )^{3/2}}{192 b}+\frac {(8 A b-a B) x \left (a+b x^2\right )^{5/2}}{48 b}+\frac {B x \left (a+b x^2\right )^{7/2}}{8 b}+\frac {\left (5 a^3 (8 A b-a B)\right ) \int \frac {1}{\sqrt {a+b x^2}} \, dx}{128 b}\\ &=\frac {5 a^2 (8 A b-a B) x \sqrt {a+b x^2}}{128 b}+\frac {5 a (8 A b-a B) x \left (a+b x^2\right )^{3/2}}{192 b}+\frac {(8 A b-a B) x \left (a+b x^2\right )^{5/2}}{48 b}+\frac {B x \left (a+b x^2\right )^{7/2}}{8 b}+\frac {\left (5 a^3 (8 A b-a B)\right ) \text {Subst}\left (\int \frac {1}{1-b x^2} \, dx,x,\frac {x}{\sqrt {a+b x^2}}\right )}{128 b}\\ &=\frac {5 a^2 (8 A b-a B) x \sqrt {a+b x^2}}{128 b}+\frac {5 a (8 A b-a B) x \left (a+b x^2\right )^{3/2}}{192 b}+\frac {(8 A b-a B) x \left (a+b x^2\right )^{5/2}}{48 b}+\frac {B x \left (a+b x^2\right )^{7/2}}{8 b}+\frac {5 a^3 (8 A b-a B) \tanh ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a+b x^2}}\right )}{128 b^{3/2}}\\ \end {align*}
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Mathematica [A]
time = 0.19, size = 123, normalized size = 0.83 \begin {gather*} \frac {x \sqrt {a+b x^2} \left (264 a^2 A b+15 a^3 B+208 a A b^2 x^2+118 a^2 b B x^2+64 A b^3 x^4+136 a b^2 B x^4+48 b^3 B x^6\right )}{384 b}+\frac {5 a^3 (-8 A b+a B) \log \left (-\sqrt {b} x+\sqrt {a+b x^2}\right )}{128 b^{3/2}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.08, size = 162, normalized size = 1.09
method | result | size |
risch | \(\frac {x \left (48 B \,x^{6} b^{3}+64 A \,b^{3} x^{4}+136 B a \,b^{2} x^{4}+208 A a \,b^{2} x^{2}+118 B \,a^{2} b \,x^{2}+264 A \,a^{2} b +15 B \,a^{3}\right ) \sqrt {b \,x^{2}+a}}{384 b}+\frac {5 a^{3} \ln \left (x \sqrt {b}+\sqrt {b \,x^{2}+a}\right ) A}{16 \sqrt {b}}-\frac {5 a^{4} \ln \left (x \sqrt {b}+\sqrt {b \,x^{2}+a}\right ) B}{128 b^{\frac {3}{2}}}\) | \(129\) |
default | \(B \left (\frac {x \left (b \,x^{2}+a \right )^{\frac {7}{2}}}{8 b}-\frac {a \left (\frac {x \left (b \,x^{2}+a \right )^{\frac {5}{2}}}{6}+\frac {5 a \left (\frac {x \left (b \,x^{2}+a \right )^{\frac {3}{2}}}{4}+\frac {3 a \left (\frac {x \sqrt {b \,x^{2}+a}}{2}+\frac {a \ln \left (x \sqrt {b}+\sqrt {b \,x^{2}+a}\right )}{2 \sqrt {b}}\right )}{4}\right )}{6}\right )}{8 b}\right )+A \left (\frac {x \left (b \,x^{2}+a \right )^{\frac {5}{2}}}{6}+\frac {5 a \left (\frac {x \left (b \,x^{2}+a \right )^{\frac {3}{2}}}{4}+\frac {3 a \left (\frac {x \sqrt {b \,x^{2}+a}}{2}+\frac {a \ln \left (x \sqrt {b}+\sqrt {b \,x^{2}+a}\right )}{2 \sqrt {b}}\right )}{4}\right )}{6}\right )\) | \(162\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.31, size = 151, normalized size = 1.01 \begin {gather*} \frac {1}{6} \, {\left (b x^{2} + a\right )}^{\frac {5}{2}} A x + \frac {5}{24} \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} A a x + \frac {5}{16} \, \sqrt {b x^{2} + a} A a^{2} x + \frac {{\left (b x^{2} + a\right )}^{\frac {7}{2}} B x}{8 \, b} - \frac {{\left (b x^{2} + a\right )}^{\frac {5}{2}} B a x}{48 \, b} - \frac {5 \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} B a^{2} x}{192 \, b} - \frac {5 \, \sqrt {b x^{2} + a} B a^{3} x}{128 \, b} - \frac {5 \, B a^{4} \operatorname {arsinh}\left (\frac {b x}{\sqrt {a b}}\right )}{128 \, b^{\frac {3}{2}}} + \frac {5 \, A a^{3} \operatorname {arsinh}\left (\frac {b x}{\sqrt {a b}}\right )}{16 \, \sqrt {b}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 1.59, size = 257, normalized size = 1.72 \begin {gather*} \left [-\frac {15 \, {\left (B a^{4} - 8 \, A a^{3} b\right )} \sqrt {b} \log \left (-2 \, b x^{2} - 2 \, \sqrt {b x^{2} + a} \sqrt {b} x - a\right ) - 2 \, {\left (48 \, B b^{4} x^{7} + 8 \, {\left (17 \, B a b^{3} + 8 \, A b^{4}\right )} x^{5} + 2 \, {\left (59 \, B a^{2} b^{2} + 104 \, A a b^{3}\right )} x^{3} + 3 \, {\left (5 \, B a^{3} b + 88 \, A a^{2} b^{2}\right )} x\right )} \sqrt {b x^{2} + a}}{768 \, b^{2}}, \frac {15 \, {\left (B a^{4} - 8 \, A a^{3} b\right )} \sqrt {-b} \arctan \left (\frac {\sqrt {-b} x}{\sqrt {b x^{2} + a}}\right ) + {\left (48 \, B b^{4} x^{7} + 8 \, {\left (17 \, B a b^{3} + 8 \, A b^{4}\right )} x^{5} + 2 \, {\left (59 \, B a^{2} b^{2} + 104 \, A a b^{3}\right )} x^{3} + 3 \, {\left (5 \, B a^{3} b + 88 \, A a^{2} b^{2}\right )} x\right )} \sqrt {b x^{2} + a}}{384 \, b^{2}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 316 vs.
\(2 (134) = 268\).
time = 35.81, size = 316, normalized size = 2.12 \begin {gather*} \frac {A a^{\frac {5}{2}} x \sqrt {1 + \frac {b x^{2}}{a}}}{2} + \frac {3 A a^{\frac {5}{2}} x}{16 \sqrt {1 + \frac {b x^{2}}{a}}} + \frac {35 A a^{\frac {3}{2}} b x^{3}}{48 \sqrt {1 + \frac {b x^{2}}{a}}} + \frac {17 A \sqrt {a} b^{2} x^{5}}{24 \sqrt {1 + \frac {b x^{2}}{a}}} + \frac {5 A a^{3} \operatorname {asinh}{\left (\frac {\sqrt {b} x}{\sqrt {a}} \right )}}{16 \sqrt {b}} + \frac {A b^{3} x^{7}}{6 \sqrt {a} \sqrt {1 + \frac {b x^{2}}{a}}} + \frac {5 B a^{\frac {7}{2}} x}{128 b \sqrt {1 + \frac {b x^{2}}{a}}} + \frac {133 B a^{\frac {5}{2}} x^{3}}{384 \sqrt {1 + \frac {b x^{2}}{a}}} + \frac {127 B a^{\frac {3}{2}} b x^{5}}{192 \sqrt {1 + \frac {b x^{2}}{a}}} + \frac {23 B \sqrt {a} b^{2} x^{7}}{48 \sqrt {1 + \frac {b x^{2}}{a}}} - \frac {5 B a^{4} \operatorname {asinh}{\left (\frac {\sqrt {b} x}{\sqrt {a}} \right )}}{128 b^{\frac {3}{2}}} + \frac {B b^{3} x^{9}}{8 \sqrt {a} \sqrt {1 + \frac {b x^{2}}{a}}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.68, size = 134, normalized size = 0.90 \begin {gather*} \frac {1}{384} \, {\left (2 \, {\left (4 \, {\left (6 \, B b^{2} x^{2} + \frac {17 \, B a b^{7} + 8 \, A b^{8}}{b^{6}}\right )} x^{2} + \frac {59 \, B a^{2} b^{6} + 104 \, A a b^{7}}{b^{6}}\right )} x^{2} + \frac {3 \, {\left (5 \, B a^{3} b^{5} + 88 \, A a^{2} b^{6}\right )}}{b^{6}}\right )} \sqrt {b x^{2} + a} x + \frac {5 \, {\left (B a^{4} - 8 \, A a^{3} b\right )} \log \left ({\left | -\sqrt {b} x + \sqrt {b x^{2} + a} \right |}\right )}{128 \, b^{\frac {3}{2}}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \left (B\,x^2+A\right )\,{\left (b\,x^2+a\right )}^{5/2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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